What is the domain of f(x)=((x+1))/((3x-1)) ?

The domain of f(x)=((x+1))/((3x-1)) is x 1/3

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domain of f(x)=((x+1))/((3x-1))

domain

f (x) = \frac{( x + 1 )}{( 3 x - 1 )}

x < \frac{1}{3} or x > \frac{1}{3}

Interval Notation

(- \infty, \frac{1}{3}) \cup (\frac{1}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{3}

The function domain

x < \frac{1}{3} or x > \frac{1}{3}

f (x) = \frac{x ^{2} - 5 x - 6}{x ^{2} - 2 x - 3}

\frac{5}{5 x + 6}

f (x) = ln (0.5 + 1)

f (x) = \frac{82}{( 9 x - 1 ) ^{2}}

\frac{7 x + 9}{x ^{2} - 9} - \frac{6 x + 6}{x ^{2} - 9}

What is the domain of f(x)=((x+1))/((3x-1)) ?
The domain of f(x)=((x+1))/((3x-1)) is x< 1/3 \lor x> 1/3