What is the domain of y= 5/(x^2+x-12) ?

The domain of y= 5/(x^2+x-12) is x 3

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domain of y= 5/(x^2+x-12)

domain

y = \frac{5}{x ^{2} + x - 12}

x < - 4 or - 4 < x < 3 or x > 3

Interval Notation

(- \infty, - 4) \cup (- 4, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 4

The function domain

x < - 4 or - 4 < x < 3 or x > 3

U (d) = - 0.33 d^{2} + 7 d + 30, d > 0

x^{2} + 4 x + 9

f (x) = \frac{2 x}{3 x - 5}

f (x) = \frac{x ^{2} + 2 x - 8}{x ^{44}}

f (x) = \frac{- 6 x ^{2}}{( x - 2 ) ( x + 6 )}

What is the domain of y= 5/(x^2+x-12) ?
The domain of y= 5/(x^2+x-12) is x<-4\lor-4<x<3\lor x>3