What is the domain of f(x)=sqrt((x-6)/(-x+9)) ?

The domain of f(x)=sqrt((x-6)/(-x+9)) is 6<= x<9

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domain of f(x)=sqrt((x-6)/(-x+9))

domain

f (x) = \frac{x - 6}{- x + 9}

6 \leq x < 9

Interval Notation

[6, 9)

Solution steps

Find non-negative values for radicals:

6 \leq x < 9

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

6 \leq x < 9

y = \frac{1}{x ( 3 - x ^{2} )}

f (x) = \frac{21 - 2 x}{x - 9}

6 - x^{2}

f (x) = - 2 x + 4

f (x) = \frac{2 x - 1}{x ^{2} - 2 x + 1}

What is the domain of f(x)=sqrt((x-6)/(-x+9)) ?
The domain of f(x)=sqrt((x-6)/(-x+9)) is 6<= x<9