What is the domain of f(x)=|(x+1)/(x-1)| ?

The domain of f(x)=|(x+1)/(x-1)| is x 1

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domain of f(x)=|(x+1)/(x-1)|

domain

f (x) = \frac{x + 1}{x - 1}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

\frac{x + 4}{x ^{2} + 5 x - 14}

f (x) = \frac{5 x ^{2}}{x ^{2} - 16}

f (x) = \frac{5 x}{x ^{2} - 12 x + 27}

9 - x^{2} + \frac{1}{x - 2}

4 x^{3} - 28 x^{2}

What is the domain of f(x)=|(x+1)/(x-1)| ?
The domain of f(x)=|(x+1)/(x-1)| is x<1\lor x>1