What is the domain of sqrt(9-x^2)+1/(x-2) ?

The domain of sqrt(9-x^2)+1/(x-2) is -3<= x<2\lor 2<x<= 3

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domain of sqrt(9-x^2)+1/(x-2)

domain

9 - x^{2} + \frac{1}{x - 2}

- 3 \leq x < 2 or 2 < x \leq 3

Interval Notation

[- 3, 2) \cup (2, 3]

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

- 3 \leq x < 2 or 2 < x \leq 3

4 x^{3} - 28 x^{2}

h (x) = - x + 4

f (a) = \frac{1}{( x + 2 ) ^{2}}

f (x) = 2 (x + 4)^{2} - 5

\frac{8 x - 1}{x + 9}

What is the domain of sqrt(9-x^2)+1/(x-2) ?
The domain of sqrt(9-x^2)+1/(x-2) is -3<= x<2\lor 2<x<= 3