What is the domain of (x^2-9)/(2x^2-3x-9) ?

The domain of (x^2-9)/(2x^2-3x-9) is x 3

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domain of (x^2-9)/(2x^2-3x-9)

domain

\frac{x ^{2} - 9}{2 x ^{2} - 3 x - 9}

x < - \frac{3}{2} or - \frac{3}{2} < x < 3 or x > 3

Interval Notation

(- \infty, - \frac{3}{2}) \cup (- \frac{3}{2}, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - \frac{3}{2}

The function domain

x < - \frac{3}{2} or - \frac{3}{2} < x < 3 or x > 3

f (x) = \frac{4 - x ^{2}}{5 x ^{2} - 3}

f (x) = 6 n - 24

f (x) = \frac{2 x + 3}{7 - 5 x}

f (x) = \frac{8 x ^{2}}{16 - x ^{2}}

h (x) = 30 - 5 x

What is the domain of (x^2-9)/(2x^2-3x-9) ?
The domain of (x^2-9)/(2x^2-3x-9) is x<-3/2 \lor-3/2 <x<3\lor x>3