What is the domain of f(x)=(3-sqrt(9-x^2))/x ?

The domain of f(x)=(3-sqrt(9-x^2))/x is -3<= x<0\lor 0<x<= 3

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domain of f(x)=(3-sqrt(9-x^2))/x

domain

f (x) = \frac{3 - 9 - x ^{2}}{x}

- 3 \leq x < 0 or 0 < x \leq 3

Interval Notation

[- 3, 0) \cup (0, 3]

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 3 \leq x < 0 or 0 < x \leq 3

f (x) = \frac{2 x}{10 - x}

h (x) = \frac{x ^{2} - 9}{x - 2}

y = e^{3} (e - 2 a)

- 3 x + 2 - 6

f (x) = \frac{3 - 7 x}{8 x}

What is the domain of f(x)=(3-sqrt(9-x^2))/x ?
The domain of f(x)=(3-sqrt(9-x^2))/x is -3<= x<0\lor 0<x<= 3