What is the domain of f(x)=(3-sqrt(x+1))/(x-8) ?

The domain of f(x)=(3-sqrt(x+1))/(x-8) is -1 8

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domain of f(x)=(3-sqrt(x+1))/(x-8)

domain

f (x) = \frac{3 - x + 1}{x - 8}

- 1 \leq x < 8 or x > 8

Interval Notation

[- 1, 8) \cup (8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = 8

Combine real regions and undefined points for final function domain

- 1 \leq x < 8 or x > 8

\frac{1}{2} - 9 x^{2} - 36 x + 3

f (x) = x \cdot lo g_{10} (π)

f (x) = \frac{π}{6} - 2 arcsin (1 - 2 x)

\frac{( x + 9 )}{( x ^{2} - 16 )}

f (x) = \frac{8 x ^{2} - 10 x}{x ^{2} + 2 x - 8}

What is the domain of f(x)=(3-sqrt(x+1))/(x-8) ?
The domain of f(x)=(3-sqrt(x+1))/(x-8) is -1<= x<8\lor x>8