What is the domain of f(x)=4sqrt(x-3)+3 ?

The domain of f(x)=4sqrt(x-3)+3 is x>= 3

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domain of f(x)=4sqrt(x-3)+3

domain

f (x) = 4 x - 3 + 3

x \geq 3

Interval Notation

[3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

The function domain

x \geq 3

y = cos (- 1 (3 - 2 x))

g (x) = - 2 + lo g_{2} (x - 3)

f (x) = \frac{4}{( 2 x + 7 ) + 3}

f (x) = lo g_{e} (9 - x^{2})

f (x) = 5 \cdot 1 - x - 3, x > - 8

What is the domain of f(x)=4sqrt(x-3)+3 ?
The domain of f(x)=4sqrt(x-3)+3 is x>= 3