What is the domain of f(x)=(3x+1)/(2x^2-7x-4) ?

The domain of f(x)=(3x+1)/(2x^2-7x-4) is x 4

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domain of f(x)=(3x+1)/(2x^2-7x-4)

domain

f (x) = \frac{3 x + 1}{2 x ^{2} - 7 x - 4}

x < - \frac{1}{2} or - \frac{1}{2} < x < 4 or x > 4

Interval Notation

(- \infty, - \frac{1}{2}) \cup (- \frac{1}{2}, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - \frac{1}{2}

The function domain

x < - \frac{1}{2} or - \frac{1}{2} < x < 4 or x > 4

f (x) = \frac{6}{x} x - 6

y = 1 - x

f (x) = \frac{( x + 1 ) ^{3}}{( x - 3 ) ^{2}}

f (x) = - 2 \cdot (0.5)^{x}

\frac{x + 1}{x + \frac{2}{3}}

What is the domain of f(x)=(3x+1)/(2x^2-7x-4) ?
The domain of f(x)=(3x+1)/(2x^2-7x-4) is x<-1/2 \lor-1/2 <x<4\lor x>4