What is the domain of g(x)=(sqrt(2+x))/(1-x) ?

The domain of g(x)=(sqrt(2+x))/(1-x) is -2 1

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domain of g(x)=(sqrt(2+x))/(1-x)

domain

g (x) = \frac{2 + x}{1 - x}

- 2 \leq x < 1 or x > 1

Interval Notation

[- 2, 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

- 2 \leq x < 1 or x > 1

\frac{1}{x + 4 - 3}

f (x) = 4 x - 6

f (x) = lo g_{3} (\frac{1}{x - 2})

f (x) = f (x) = \frac{2}{x}

cos (arctan (x))

What is the domain of g(x)=(sqrt(2+x))/(1-x) ?
The domain of g(x)=(sqrt(2+x))/(1-x) is -2<= x<1\lor x>1