What is the domain of f(x)=(|x-1|)/(x-1)x^2 ?

The domain of f(x)=(|x-1|)/(x-1)x^2 is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(|x-1|)/(x-1)x^2

domain

f (x) = \frac{∣ x - 1 ∣}{x - 1} x^{2}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

f (x) = \frac{x ^{2}}{9} + \frac{( y - 5 ) ^{2}}{25} = 1

+ (- 3) x + 3

f (x) = (x^{2} - 4) (x + 6)

x (160 - x)

9 - (x - 1)^{2}

What is the domain of f(x)=(|x-1|)/(x-1)x^2 ?
The domain of f(x)=(|x-1|)/(x-1)x^2 is x<1\lor x>1