What is the domain of f(x)=((x^2))/(sqrt(x^4+2)) ?

The domain of f(x)=((x^2))/(sqrt(x^4+2)) is -infinity <x<infinity

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domain of f(x)=((x^2))/(sqrt(x^4+2))

domain

f (x) = \frac{( x ^{2} )}{x ^{4} + 2}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = ln (13 x)

f (x) = \frac{\frac{1}{( x + 1 )}}{x ^{2} - 4}

f (x) = x^{3} - 2 x^{2}

x + 2 - 8

f (x) = \frac{( t + 2 )}{15 - t}

What is the domain of f(x)=((x^2))/(sqrt(x^4+2)) ?
The domain of f(x)=((x^2))/(sqrt(x^4+2)) is -infinity <x<infinity