What is the domain of f(x)= 3/(sqrt(x+1)-2) ?

The domain of f(x)= 3/(sqrt(x+1)-2) is -1 3

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domain of f(x)= 3/(sqrt(x+1)-2)

domain

f (x) = \frac{3}{x + 1 - 2}

- 1 \leq x < 3 or x > 3

Interval Notation

[- 1, 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

- 1 \leq x < 3 or x > 3

f (x) = (e^{\frac{1}{x}})^{3}

f (x) = (9 - x^{2})^{2} - 9

2 arcsin (3 x + 1) - \frac{π}{2}

y = \frac{x - 4}{x ^{2}}

8 x^{4} - 14 x^{3} - 9 x^{2} + 11 x - 1

What is the domain of f(x)= 3/(sqrt(x+1)-2) ?
The domain of f(x)= 3/(sqrt(x+1)-2) is -1<= x<3\lor x>3