What is the domain of f(x)=(-2x^2+3)/(sqrt(3x-5)) ?

The domain of f(x)=(-2x^2+3)/(sqrt(3x-5)) is x> 5/3

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domain of f(x)=(-2x^2+3)/(sqrt(3x-5))

domain

f (x) = \frac{- 2 x ^{2} + 3}{3 x - 5}

x > \frac{5}{3}

Interval Notation

(\frac{5}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{5}{3}

Find undefined (singularity) points:

x = \frac{5}{3}

Combine real regions and undefined points for final function domain

x > \frac{5}{3}

f (x) = 2 x - 1, x < 1

f (x) = \frac{( x ^{2} + 13 x + 36 )}{x ^{2} - 1}

f (x) = ln (x) - ln (x + 2)

f (x) = 2 cos (t) + sin (2 t)

2 x - 2 sin (x)

What is the domain of f(x)=(-2x^2+3)/(sqrt(3x-5)) ?
The domain of f(x)=(-2x^2+3)/(sqrt(3x-5)) is x> 5/3