What is the domain of f(x)= 4/(sqrt(x^2+6x)) ?

The domain of f(x)= 4/(sqrt(x^2+6x)) is x 0

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domain of f(x)= 4/(sqrt(x^2+6x))

domain

f (x) = \frac{4}{x ^{2} + 6 x}

x < - 6 or x > 0

Interval Notation

(- \infty, - 6) \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 6 or x \geq 0

Find undefined (singularity) points:

x = 0, x = - 6

Combine real regions and undefined points for final function domain

x < - 6 or x > 0

\frac{x ^{2} + x - 2}{x + 3}

y = (arccos (\frac{2 x}{1 + x}))

f (x) = e^{2} x - 3 e x + 2

f (x) = \frac{2}{( 1 - 2 x )}

\frac{x ^{2} - 2 x}{6 x} - \frac{3 x ^{2} - 15 x}{6 x}

What is the domain of f(x)= 4/(sqrt(x^2+6x)) ?
The domain of f(x)= 4/(sqrt(x^2+6x)) is x<-6\lor x>0