What is the domain of (8x^2+12x)/(9x^2-12x+4) ?

The domain of (8x^2+12x)/(9x^2-12x+4) is x 2/3

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domain of (8x^2+12x)/(9x^2-12x+4)

domain

\frac{8 x ^{2} + 12 x}{9 x ^{2} - 12 x + 4}

x < \frac{2}{3} or x > \frac{2}{3}

Interval Notation

(- \infty, \frac{2}{3}) \cup (\frac{2}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{2}{3}

The function domain

x < \frac{2}{3} or x > \frac{2}{3}

\frac{- x ^{2} + 7 x - 10}{x - 3}

f (x) = 1 - \frac{x ^{2}}{16}

f (x) = \frac{1 - 3 x}{x ^{3} - 4 x ^{2} - 5 x}

\frac{\frac{2}{x}}{\frac{4}{x + 4}}

f (x) = (x - 1)^{(2)} + 3

What is the domain of (8x^2+12x)/(9x^2-12x+4) ?
The domain of (8x^2+12x)/(9x^2-12x+4) is x< 2/3 \lor x> 2/3