What is the domain of 1/(sqrt(x^2+10)) ?

The domain of 1/(sqrt(x^2+10)) is -infinity <x<infinity

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domain of 1/(sqrt(x^2+10))

domain

\frac{1}{x ^{2} + 10}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{1}{2 x ^{2} + 1}

f (x) = \frac{x ^{2} + 7 x + 13}{x + 4}

f (x) = x^{5} - 2 x^{3} - x

\frac{- 2 + x}{4 x - \frac{1}{4}} + 3

f (x) = 10 - 9 x + 6

What is the domain of 1/(sqrt(x^2+10)) ?
The domain of 1/(sqrt(x^2+10)) is -infinity <x<infinity