What is the domain of f(x)=1-sqrt(1-x^2) ?

The domain of f(x)=1-sqrt(1-x^2) is -1<= x<= 1

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domain of f(x)=1-sqrt(1-x^2)

domain

f (x) = 1 - 1 - x^{2}

- 1 \leq x \leq 1

Interval Notation

[- 1, 1]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

The function domain

- 1 \leq x \leq 1

ln (6 x - 5)

f (x) = 2 x - 6

f (x) = \frac{1}{t - 9}

f (x) = \frac{( 2 x - 3 )}{x + 1}

What is the domain of f(x)=1-sqrt(1-x^2) ?
The domain of f(x)=1-sqrt(1-x^2) is -1<= x<= 1