What is the domain of f(x)=((2x-3))/(x+1) ?

The domain of f(x)=((2x-3))/(x+1) is x -1

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domain of f(x)=((2x-3))/(x+1)

domain

f (x) = \frac{( 2 x - 3 )}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

y = lo g_{10} (3 - 4 x)

f (x) = \frac{35 x}{4 x - 6}

\frac{7 + 6 x - x ^{2}}{x + 3}

f (x) = \frac{x ^{3}}{x + 2}

f (x) = \frac{2 x ^{2} + 1}{\frac{1}{16} x ^{2} + 3}

What is the domain of f(x)=((2x-3))/(x+1) ?
The domain of f(x)=((2x-3))/(x+1) is x<-1\lor x>-1