What is the domain of-sqrt(16x^2-49x) ?

The domain of-sqrt(16x^2-49x) is x = 49/16

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domain of-sqrt(16x^2-49x)

domain

- 16 x^{2} - 49 x

x \leq 0 or x \geq \frac{49}{16}

Interval Notation

(- \infty, 0] \cup [\frac{49}{16}, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq \frac{49}{16}

The function domain

x \leq 0 or x \geq \frac{49}{16}

- 6 x^{2} (5 x - 3)

f (x) = \frac{x ^{2}}{x ^{2} + x - 20}

f (x) = 1 + \frac{3}{2 x}

\frac{X - 16}{X - 81}

1 - \frac{x + 2}{2 x - 1} + 5 - x

What is the domain of-sqrt(16x^2-49x) ?
The domain of-sqrt(16x^2-49x) is x<= 0\lor x>= 49/16