What is the domain of f(x)=sqrt(1+3/(2x)) ?

The domain of f(x)=sqrt(1+3/(2x)) is x 0

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domain of f(x)=sqrt(1+3/(2x))

domain

f (x) = 1 + \frac{3}{2 x}

x \leq - \frac{3}{2} or x > 0

Interval Notation

(- \infty, - \frac{3}{2}] \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - \frac{3}{2} or x > 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x \leq - \frac{3}{2} or x > 0

\frac{X - 16}{X - 81}

1 - \frac{x + 2}{2 x - 1} + 5 - x

f (x) = \frac{sin ( x )}{x - π}

f (x) = - 4 + 17 x - 19

f (x) = \frac{\frac{1}{x} - 3}{3}

What is the domain of f(x)=sqrt(1+3/(2x)) ?
The domain of f(x)=sqrt(1+3/(2x)) is x<=-3/2 \lor x>0