What is the domain of f(x)=(1/x-3)/3 ?

The domain of f(x)=(1/x-3)/3 is x 0

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domain of f(x)=(1/x-3)/3

domain

f (x) = \frac{\frac{1}{x} - 3}{3}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

f (x) = \frac{x - 1}{x ^{2} + 6 x - 16}

y = x - 2, x \geq 2

arccos (\frac{2 arcsin ( \frac{1}{4 x ^{2} - 1} )}{π})

f (x) = 84 x^{2} - x^{3}

What is the domain of f(x)=(1/x-3)/3 ?
The domain of f(x)=(1/x-3)/3 is x<0\lor x>0