What is the domain of \sqrt[3]{x^2-4} ?

The domain of \sqrt[3]{x^2-4} is -infinity <x<infinity

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domain of \sqrt[3]{x^2-4}

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = x - 2, x \geq 2

arccos (\frac{2 arcsin ( \frac{1}{4 x ^{2} - 1} )}{π})

f (x) = 84 x^{2} - x^{3}

\frac{\frac{8}{x + 6}}{\frac{7}{x}}

f (x) = \frac{x}{4 x - 9}

What is the domain of \sqrt[3]{x^2-4} ?
The domain of \sqrt[3]{x^2-4} is -infinity <x<infinity