What is the domain of f(x)=(x-8)/(x^2-3x-40) ?

The domain of f(x)=(x-8)/(x^2-3x-40) is x 8

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domain of f(x)=(x-8)/(x^2-3x-40)

domain

f (x) = \frac{x - 8}{x ^{2} - 3 x - 40}

x < - 5 or - 5 < x < 8 or x > 8

Interval Notation

(- \infty, - 5) \cup (- 5, 8) \cup (8, \infty)

Solution steps

Find undefined (singularity) points:

x = 8, x = - 5

The function domain

x < - 5 or - 5 < x < 8 or x > 8

\frac{sin ( x )}{7 - e ^{2 x - 3}}

f (x) = \frac{x - 2}{x ^{2} + x - 2}

y = x^{2} + 36

f (t) = 55 + 35

v (x) = \frac{x}{x ^{2} + 64}

What is the domain of f(x)=(x-8)/(x^2-3x-40) ?
The domain of f(x)=(x-8)/(x^2-3x-40) is x<-5\lor-5<x<8\lor x>8