What is the domain of f(x)=(39x)/(x^2-5x-14) ?

The domain of f(x)=(39x)/(x^2-5x-14) is x 7

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domain of f(x)=(39x)/(x^2-5x-14)

domain

f (x) = \frac{39 x}{x ^{2} - 5 x - 14}

x < - 2 or - 2 < x < 7 or x > 7

Interval Notation

(- \infty, - 2) \cup (- 2, 7) \cup (7, \infty)

Solution steps

Find undefined (singularity) points:

x = 7, x = - 2

The function domain

x < - 2 or - 2 < x < 7 or x > 7

\frac{x + 6}{x - 6}

f (x) = \frac{( - 3 x ^{2} + 4 )}{4 x ^{2} + 5}

f (x) = \frac{lo g _{\frac{1}{2}} ( 1 )}{x ^{2} - 5 x}

f (x) = \frac{8 + x}{7 - x}

4 (x) + 1

What is the domain of f(x)=(39x)/(x^2-5x-14) ?
The domain of f(x)=(39x)/(x^2-5x-14) is x<-2\lor-2<x<7\lor x>7