What is the domain of sqrt((x-10)(x+2)) ?

The domain of sqrt((x-10)(x+2)) is x = 10

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domain of sqrt((x-10)(x+2))

domain

(x - 10) (x + 2)

x \leq - 2 or x \geq 10

Interval Notation

(- \infty, - 2] \cup [10, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 10

The function domain

x \leq - 2 or x \geq 10

\frac{- 3 x + 5}{2}, - 1 \leq x < 4

\frac{1}{1 + \frac{1}{1 + \frac{1}{x}}}

\frac{x ^{2} - 16}{x ^{3} + 5 x ^{2} + 6 x}

f (x) = ln (9 - 4 x)

f (x) = (x + 2)^{2} + (y - 5)^{2} = 16

What is the domain of sqrt((x-10)(x+2)) ?
The domain of sqrt((x-10)(x+2)) is x<=-2\lor x>= 10