What is the domain of x/(\sqrt[3]{x^3+8)} ?

The domain of x/(\sqrt[3]{x^3+8)} is x -2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of x/(\sqrt[3]{x^3+8)}

domain

x < - 2 or x > - 2

Interval Notation

(- \infty, - 2) \cup (- 2, \infty)

Solution steps

Find undefined (singularity) points:

x = - 2

The function domain

x < - 2 or x > - 2

200000 \cdot x \cdot e^{- 0.04 x}

\frac{4 x ^{2} - 24 x + 37}{x ^{2} - 6 x + 9}

\frac{x ^{2} - x - 2}{x ^{2} + x - 6}

f (x) = \frac{2 ( x + 2 )}{3 x + 17}

f (x) = - 4 (x - 7) (x - 3)

What is the domain of x/(\sqrt[3]{x^3+8)} ?
The domain of x/(\sqrt[3]{x^3+8)} is x<-2\lor x>-2