What is the domain of f(x)=(2(x+2))/(3x+17) ?

The domain of f(x)=(2(x+2))/(3x+17) is x -17/3

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domain of f(x)=(2(x+2))/(3x+17)

domain

f (x) = \frac{2 ( x + 2 )}{3 x + 17}

x < - \frac{17}{3} or x > - \frac{17}{3}

Interval Notation

(- \infty, - \frac{17}{3}) \cup (- \frac{17}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{17}{3}

The function domain

x < - \frac{17}{3} or x > - \frac{17}{3}

f (x) = - 4 (x - 7) (x - 3)

g (x) = 16 - x^{4}

\frac{2 x + 10}{x ^{2} - 4 x - 5}

f (x) = \frac{2 x ^{2} + 2}{x + 2}

R (x) = (\frac{( x + 2 )}{( x + 5 )})

What is the domain of f(x)=(2(x+2))/(3x+17) ?
The domain of f(x)=(2(x+2))/(3x+17) is x<-17/3 \lor x>-17/3