What is the domain of 1/(2x(x-8)(9x+5)) ?

The domain of 1/(2x(x-8)(9x+5)) is x 8

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domain of 1/(2x(x-8)(9x+5))

domain

\frac{1}{2 x ( x - 8 ) ( 9 x + 5 )}

x < - \frac{5}{9} or - \frac{5}{9} < x < 0 or 0 < x < 8 or x > 8

Interval Notation

(- \infty, - \frac{5}{9}) \cup (- \frac{5}{9}, 0) \cup (0, 8) \cup (8, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = 8, x = - \frac{5}{9}

The function domain

x < - \frac{5}{9} or - \frac{5}{9} < x < 0 or 0 < x < 8 or x > 8

f (x) = \frac{1}{∣ x - 4 ∣ - 4}

f (x) = 16 - x^{2} - 4 - x

g (x) = \frac{1}{3 x}

y = - 3

x = 3 - 2^{6 y + 1}

What is the domain of 1/(2x(x-8)(9x+5)) ?
The domain of 1/(2x(x-8)(9x+5)) is x<-5/9 \lor-5/9 <x<0\lor 0<x<8\lor x>8