What is the domain of f(x)=sqrt(16-x^2)-4-x ?

The domain of f(x)=sqrt(16-x^2)-4-x is -4<= x<= 4

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domain of f(x)=sqrt(16-x^2)-4-x

domain

f (x) = 16 - x^{2} - 4 - x

- 4 \leq x \leq 4

Interval Notation

[- 4, 4]

Solution steps

Find non-negative values for radicals:

- 4 \leq x \leq 4

The function domain

- 4 \leq x \leq 4

g (x) = \frac{1}{3 x}

y = - 3

x = 3 - 2^{6 y + 1}

X^{2} + 2 X - 8

f (x, y) = 1 - y^{2}

What is the domain of f(x)=sqrt(16-x^2)-4-x ?
The domain of f(x)=sqrt(16-x^2)-4-x is -4<= x<= 4