What is the domain of f(x,y)=sqrt(1-y^2) ?

The domain of f(x,y)=sqrt(1-y^2) is -1<= y<= 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x,y)=sqrt(1-y^2)

domain

f (x, y) = 1 - y^{2}

- 1 \leq y \leq 1

Interval Notation

[- 1, 1]

Solution steps

Find non-negative values for radicals:

- 1 \leq y \leq 1

The function domain

- 1 \leq y \leq 1

f (x) = \frac{x ^{3} + 2}{x}

f (x) = 9 - 4^{2}

f (x) = x^{3} + 9 x^{2} + 26 x + 24

\frac{1 + x}{x}

f (x) = x^{2} + 6 x + 10

What is the domain of f(x,y)=sqrt(1-y^2) ?
The domain of f(x,y)=sqrt(1-y^2) is -1<= y<= 1