What is the domain of f(x)=sqrt(x^3+9x^2+26x+24) ?

The domain of f(x)=sqrt(x^3+9x^2+26x+24) is -4 =-2

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domain of f(x)=sqrt(x^3+9x^2+26x+24)

domain

f (x) = x^{3} + 9 x^{2} + 26 x + 24

- 4 \leq x \leq - 3 or x \geq - 2

Interval Notation

[- 4, - 3] \cup [- 2, \infty)

Solution steps

Find non-negative values for radicals:

- 4 \leq x \leq - 3 or x \geq - 2

The function domain

- 4 \leq x \leq - 3 or x \geq - 2

\frac{1 + x}{x}

f (x) = x^{2} + 6 x + 10

e^{\frac{( 2 - 3 x )}{x + 1}}

y = \frac{x - 1}{x + 1} + \frac{x + 1}{x - 3}

f (x) = lo g_{10} (16 - x^{2}) + 1

What is the domain of f(x)=sqrt(x^3+9x^2+26x+24) ?
The domain of f(x)=sqrt(x^3+9x^2+26x+24) is -4<= x<=-3\lor x>=-2