What is the domain of y=(x-1)/(x+1)+(x+1)/(x-3) ?

The domain of y=(x-1)/(x+1)+(x+1)/(x-3) is x 3

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domain of y=(x-1)/(x+1)+(x+1)/(x-3)

domain

y = \frac{x - 1}{x + 1} + \frac{x + 1}{x - 3}

x < - 1 or - 1 < x < 3 or x > 3

Interval Notation

(- \infty, - 1) \cup (- 1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = 3

The function domain

x < - 1 or - 1 < x < 3 or x > 3

f (x) = lo g_{10} (16 - x^{2}) + 1

f (x) = 200 x - x^{2} - 4000

g (x) = x + 4 + 3

y = 2^{\frac{x}{2}}

What is the domain of y=(x-1)/(x+1)+(x+1)/(x-3) ?
The domain of y=(x-1)/(x+1)+(x+1)/(x-3) is x<-1\lor-1<x<3\lor x>3