What is the domain of h(x)=\sqrt[8]{4x-10} ?

The domain of h(x)=\sqrt[8]{4x-10} is x>= 5/2

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domain of h(x)=\sqrt[8]{4x-10}

domain

x \geq \frac{5}{2}

Interval Notation

[\frac{5}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{5}{2}

The function domain

x \geq \frac{5}{2}

f (x) = \frac{x}{7 x + 11}

f (x) = \frac{( 2 x + 3 ) ( x - 1 )}{( x - 1 )}

8 (8 x + 9) + 9

f (x) = \frac{3}{4 + \frac{5}{x}}

r (x) = \frac{x ^{2} - 2 x - 8}{x ^{2} + 4 x}

What is the domain of h(x)=\sqrt[8]{4x-10} ?
The domain of h(x)=\sqrt[8]{4x-10} is x>= 5/2