What is the domain of f(x)=(x^2+1)/2 ?

The domain of f(x)=(x^2+1)/2 is -infinity <x<infinity

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domain of f(x)=(x^2+1)/2

domain

f (x) = \frac{x ^{2} + 1}{2}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

g (x) = - 8 x + 48

f (x) = x - \frac{1}{2} (x + 1)^{2} - 2

\frac{( 8 x ^{2} + 12 x )}{( 3 x - 2 ) ^{2}}

f (x) = \frac{( x - 6 )}{x + 9}

f (x) = \frac{( - x ^{2} + 1 )}{( x ^{2} + 2 x - 3 )}

What is the domain of f(x)=(x^2+1)/2 ?
The domain of f(x)=(x^2+1)/2 is -infinity <x<infinity