What is the domain of sqrt(x^2-4)sqrt(x^2-9) ?

The domain of sqrt(x^2-4)sqrt(x^2-9) is x = 3

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domain of sqrt(x^2-4)sqrt(x^2-9)

domain

x^{2} - 4 x^{2} - 9

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

The function domain

x \leq - 3 or x \geq 3

y = \frac{x - 1}{x}

f (x) = \frac{- 5}{4 + x}

x^{2} + 12 x

81 (x - 3)^{4} (2 - (x - 3))

y = 5 (x - 5) + 40

What is the domain of sqrt(x^2-4)sqrt(x^2-9) ?
The domain of sqrt(x^2-4)sqrt(x^2-9) is x<=-3\lor x>= 3