What is the domain of f(x)=sqrt((x-3)(x+9)) ?

The domain of f(x)=sqrt((x-3)(x+9)) is x = 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt((x-3)(x+9))

domain

f (x) = (x - 3) (x + 9)

x \leq - 9 or x \geq 3

Interval Notation

(- \infty, - 9] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 9 or x \geq 3

The function domain

x \leq - 9 or x \geq 3

f (x) = 2^{x - 1} - 1

f (x) = \frac{x}{4 - ln ^{2} ( x )}

x - 3 + \frac{x + 4}{x ^{2} - 9 x + 8}

f (x) = 2 x^{2} + 16 x - 1

f (x) = \frac{3 x ^{3} + 5}{1 - x ^{3}}

What is the domain of f(x)=sqrt((x-3)(x+9)) ?
The domain of f(x)=sqrt((x-3)(x+9)) is x<=-9\lor x>= 3