What is the domain of sqrt(x-3)+(x+4)/(x^2-9x+8) ?

The domain of sqrt(x-3)+(x+4)/(x^2-9x+8) is 3 8

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domain of sqrt(x-3)+(x+4)/(x^2-9x+8)

domain

x - 3 + \frac{x + 4}{x ^{2} - 9 x + 8}

3 \leq x < 8 or x > 8

Interval Notation

[3, 8) \cup (8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

Find undefined (singularity) points:

x = 8, x = 1

Combine real regions and undefined points for final function domain

3 \leq x < 8 or x > 8

f (x) = 2 x^{2} + 16 x - 1

f (x) = \frac{3 x ^{3} + 5}{1 - x ^{3}}

\frac{x ^{\frac{1}{2}}}{( x - 3 )}

- 0.015 x^{2} + 1.22 x - 7.2

f (x) = ln (x^{2} - 8 x + 15)

What is the domain of sqrt(x-3)+(x+4)/(x^2-9x+8) ?
The domain of sqrt(x-3)+(x+4)/(x^2-9x+8) is 3<= x<8\lor x>8