What is the domain of 1/(\frac{2){x-1}+2} ?

The domain of 1/(\frac{2){x-1}+2} is x 1

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domain of 1/(\frac{2){x-1}+2}

domain

\frac{1}{\frac{2}{x - 1} + 2}

x < 0 or 0 < x < 1 or x > 1

Interval Notation

(- \infty, 0) \cup (0, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = 1

The function domain

x < 0 or 0 < x < 1 or x > 1

5 - x + 6

f (x) = \frac{x + 8}{x ^{2} + 4}

\frac{x ^{2} - 1}{- x ^{2} + 5}

f (x) = \frac{x}{17 x - 4}

What is the domain of 1/(\frac{2){x-1}+2} ?
The domain of 1/(\frac{2){x-1}+2} is x<0\lor 0<x<1\lor x>1