What is the domain of f(x)=-sqrt(-15x^2+14x-3) ?

The domain of f(x)=-sqrt(-15x^2+14x-3) is 1/3 <= x<= 3/5

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domain of f(x)=-sqrt(-15x^2+14x-3)

domain

f (x) = - - 15 x^{2} + 14 x - 3

\frac{1}{3} \leq x \leq \frac{3}{5}

Interval Notation

[\frac{1}{3}, \frac{3}{5}]

Solution steps

Find non-negative values for radicals:

\frac{1}{3} \leq x \leq \frac{3}{5}

The function domain

\frac{1}{3} \leq x \leq \frac{3}{5}

f (x) = \frac{x - 15}{x + 8}

\frac{12 - x - x ^{2}}{∣ 2 x - 5 ∣}

f (x) = e^{\frac{x ^{2} - 1}{x}}

\frac{8}{x ^{2} + x - 6} - \frac{7}{x ^{2} - x - 2}

f (x) = \frac{x - 5}{( x ^{2} - 9 )}

What is the domain of f(x)=-sqrt(-15x^2+14x-3) ?
The domain of f(x)=-sqrt(-15x^2+14x-3) is 1/3 <= x<= 3/5