What is the domain of f(x)= 4/((x-1))+1 ?

The domain of f(x)= 4/((x-1))+1 is x 1

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domain of f(x)= 4/((x-1))+1

domain

f (x) = \frac{4}{( x - 1 )} + 1

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

g (x) = 4 x - 1 h (x) = x - 3

g (x) = \frac{( x + 7 ) ^{2}}{6 x - 2}

\frac{ln ( x ^{2} )}{x ^{2} - 1}

f (x) = lo g_{10} (4 x + 3) - 2

f (x) = ln (x + 3) + ln (x - 3)

What is the domain of f(x)= 4/((x-1))+1 ?
The domain of f(x)= 4/((x-1))+1 is x<1\lor x>1