What is the domain of f(x)=sqrt(x^2-x^4) ?

The domain of f(x)=sqrt(x^2-x^4) is -1<= x<= 1

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domain of f(x)=sqrt(x^2-x^4)

domain

f (x) = x^{2} - x^{4}

- 1 \leq x \leq 1

Interval Notation

[- 1, 1]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

The function domain

- 1 \leq x \leq 1

y = x^{2} - 3 x - 4

y = 4 x - \frac{1}{5}

5 x + 5 x - 6

\frac{x - 6}{2 x - 5}

f (x) = \frac{3}{x} - 5

What is the domain of f(x)=sqrt(x^2-x^4) ?
The domain of f(x)=sqrt(x^2-x^4) is -1<= x<= 1