What is the domain of y=(1+6x)/(x-1) ?

The domain of y=(1+6x)/(x-1) is x 1

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domain of y=(1+6x)/(x-1)

domain

y = \frac{1 + 6 x}{x - 1}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

h (x) = (5 x - 25)^{- 2}

h (x) = \frac{1}{x - 9}

f (x) = \frac{1}{x ^{2 - 8 x + 16}}

\frac{x + 3}{2 x ^{2} + 2}

f (x) = \frac{x ^{2} - 4 x - 12}{x - 2}

What is the domain of y=(1+6x)/(x-1) ?
The domain of y=(1+6x)/(x-1) is x<1\lor x>1