What is the domain of f(x)=((2-x))/((x+1)^5) ?

The domain of f(x)=((2-x))/((x+1)^5) is x -1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=((2-x))/((x+1)^5)

domain

f (x) = \frac{( 2 - x )}{( x + 1 ) ^{5}}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = x^{3} - 4 x^{2} - 12 x

e^{0.5 x} + 1 6^{- x}

- 24.708 x + 111

f (x) = e^{x^{2} - 1} + ln (∣ x ∣ + 1)

y = - 2 lo g_{7} (x + 1)

What is the domain of f(x)=((2-x))/((x+1)^5) ?
The domain of f(x)=((2-x))/((x+1)^5) is x<-1\lor x>-1