What is the domain of f(x)=sqrt(x^3-4x^2-12x) ?

The domain of f(x)=sqrt(x^3-4x^2-12x) is -2 = 6

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domain of f(x)=sqrt(x^3-4x^2-12x)

domain

f (x) = x^{3} - 4 x^{2} - 12 x

- 2 \leq x \leq 0 or x \geq 6

Interval Notation

[- 2, 0] \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 0 or x \geq 6

The function domain

- 2 \leq x \leq 0 or x \geq 6

e^{0.5 x} + 1 6^{- x}

- 24.708 x + 111

f (x) = e^{x^{2} - 1} + ln (∣ x ∣ + 1)

y = - 2 lo g_{7} (x + 1)

\frac{2 x ^{2} - 9 x + 10}{2 x ^{2} + 7 x + 6}

What is the domain of f(x)=sqrt(x^3-4x^2-12x) ?
The domain of f(x)=sqrt(x^3-4x^2-12x) is -2<= x<= 0\lor x>= 6