What is the domain of y=(sin(arccos((2x)/(1+x)))) ?

The domain of y=(sin(arccos((2x)/(1+x)))) is -1/3 <= x<= 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=(sin(arccos((2x)/(1+x))))

domain

y = (sin (arccos (\frac{2 x}{1 + x})))

- \frac{1}{3} \leq x \leq 1

Interval Notation

[- \frac{1}{3}, 1]

Solution steps

Find known functions domain restrictions:

- \frac{1}{3} \leq x \leq 1

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

- \frac{1}{3} \leq x \leq 1

\frac{( 2 X - 1 )}{2} + \frac{( X + 2 )}{3}

\frac{m + 2}{2 m + 3} + \frac{5}{m - 2}

g (x) = 5 x - 40

y = \frac{1}{lo g _{10} ( x + 2 )}

What is the domain of y=(sin(arccos((2x)/(1+x)))) ?
The domain of y=(sin(arccos((2x)/(1+x)))) is -1/3 <= x<= 1