What is the domain of y= 1/(log_{10)(x+2)} ?

The domain of y= 1/(log_{10)(x+2)} is -2 -1

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domain of y= 1/(log_{10)(x+2)}

domain

y = \frac{1}{lo g _{10} ( x + 2 )}

- 2 < x < - 1 or x > - 1

Interval Notation

(- 2, - 1) \cup (- 1, \infty)

Solution steps

Find positive values for logs:

x > - 2

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

- 2 < x < - 1 or x > - 1

f (x) = \frac{x}{3 x + 9}

f (x) = x^{5} - 1

7 - e^{2 x}

y = 3 - ∣ x + 1 ∣

4 x^{2} - 4, x \geq 0

What is the domain of y= 1/(log_{10)(x+2)} ?
The domain of y= 1/(log_{10)(x+2)} is -2<x<-1\lor x>-1