What is the domain of f(x)= 1/(\sqrt[4]{10+x)} ?

The domain of f(x)= 1/(\sqrt[4]{10+x)} is x>-10

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domain of f(x)= 1/(\sqrt[4]{10+x)}

domain

x > - 10

Interval Notation

(- 10, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 10

Find undefined (singularity) points:

x = - 10

Combine real regions and undefined points for final function domain

x > - 10

\frac{x - 8}{3 x - 4}

f (x) = - x^{2} + 6 x - 4, 2 \leq x \leq 7

\frac{3 x ( x - 9 )}{6 x ^{2} - 41 x - 7}

\frac{x ^{2} + x}{8 x - 32}

\frac{6 x ^{2} + 19 x + 8}{x ^{4} - 98 x ^{2} + 2401}

What is the domain of f(x)= 1/(\sqrt[4]{10+x)} ?
The domain of f(x)= 1/(\sqrt[4]{10+x)} is x>-10