What is the inverse of f(x)= 1/4 x^3-3 ?

The inverse of f(x)= 1/4 x^3-3 is cube root of 4x+12

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inverse of f(x)= 1/4 x^3-3

inverse

f (x) = \frac{1}{4} x^{3} - 3

Solution steps

y = \frac{1}{4} x^{3} - 3

Replace

x

with

y

x = \frac{1}{4} y^{3} - 3

Solve for

y, x = \frac{1}{4} y^{3} - 3

f (x) = \frac{2 x + 7}{x ^{3} - 5 x ^{2} - 4 x + 20}

f (x) = \frac{x - 2}{1 - 3 x}

sin (x + \frac{3 π}{2})

4 x^{2} + 2

\frac{3 x + 1}{x - 2}

What is the inverse of f(x)= 1/4 x^3-3 ?
The inverse of f(x)= 1/4 x^3-3 is cube root of 4x+12